Quantcast
Channel: "Continuized" Taylor Series? $\sin(x)=\sum \frac{(-1)^nx^{2n+1}}{(2n+1)!}=\int_{-1}^\infty \frac{\cos(\pi n) x^{2n+1}}{G(2n+1)}dn$? - Mathematics Stack Exchange
Browsing latest articles
Browse All 3 View Live

Answer by timur for "Continuized" Taylor Series? $\sin(x)=\sum...

Here is a partial answer to some of the questions.In this book, page 217 (see also this thread), it was established that$$f(z)=\int_0^\infty\frac{z^tdt}{\Gamma(t+1)} = e^z+O(|z|^{-N}),$$for any integer...

View Article



Answer by Winther for "Continuized" Taylor Series? $\sin(x)=\sum...

In none of the cases you have put up is there a perfect equality. The functions you define are just approximately the same as the corresponding infinite series (it's easy to prove this; just select one...

View Article

Image may be NSFW.
Clik here to view.

"Continuized" Taylor Series? $\sin(x)=\sum...

~~not trying to reinvent the Laplace transform, but just an exploration into these particular series and integrals~~Current answers don't fully address the 5 questions, so any new ideas or suggestions...

View Article
Browsing latest articles
Browse All 3 View Live


Latest Images

<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>
<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596344.js" async> </script>